use grid::Grid; use itertools::Itertools; use std::collections::HashSet; use std::fs::File; use std::io::{BufRead, BufReader, Lines}; use std::time::{Duration, Instant}; // BOILERPLATE type InputIter = Lines>; pub fn get_input() -> InputIter { let f = File::open("input").unwrap(); let br = BufReader::new(f); br.lines() } fn duration_format(duration: Duration) -> String { match duration.as_secs_f64() { x if x > 1.0 => format!("{:.3}s", x), x if x > 0.010 => format!("{:.3}ms", x * 1e3), x => format!("{:.3}us", x * 1e6), } } fn main() { let input = get_input(); let start = Instant::now(); let ans1 = problem1(input); let duration1 = start.elapsed(); println!("Problem 1 solution: {} [{}]", ans1, duration_format(duration1)); let input = get_input(); let start = Instant::now(); let ans2 = problem2(input); let duration2 = start.elapsed(); println!("Problem 2 solution: {} [{}]", ans2, duration_format(duration2)); println!("Total duration: {}", duration_format(duration1 + duration2)); } struct AntennaMap { map: Grid, antinodes: Grid, } impl From> for AntennaMap { fn from(input: Lines) -> Self { let map = Grid::from(input); let width = map.width(); let height = map.height(); Self { map, antinodes: Grid::with_shape(width, height, b'.'), } } } // PROBLEM 1 solution fn problem1(input: Lines) -> u64 { let mut map = AntennaMap::from(input); // find the unique frequencies in a dumb way let freq_set: HashSet<&u8> = HashSet::from_iter(map.map.data.iter().filter(|c| **c != b'.')); // for each unique frequency, get all the pairs' positions for freq in freq_set { let coords = map .map .data .iter() .enumerate() .filter(|(_, c)| *c == freq) .map(|(i, _)| map.map.coord(i as i64).unwrap()) .collect_vec(); for pair in coords.iter().permutations(2).collect_vec() { let (a, b) = (pair[0], pair[1]); let node_pos = (a.0 + a.0 - b.0, a.1 + a.1 - b.1); map.antinodes.set(node_pos.0, node_pos.1, b'#'); } } map.antinodes.count(b'#') as u64 } // PROBLEM 2 solution fn problem2(input: Lines) -> u64 { let mut map = AntennaMap::from(input); // find the unique frequencies in a dumb way let freq_set: HashSet<&u8> = HashSet::from_iter(map.map.data.iter().filter(|c| **c != b'.')); // for each unique frequency, get all the pairs' positions for freq in freq_set { let coords = map .map .data .iter() .enumerate() .filter(|(_, c)| *c == freq) .map(|(i, _)| map.map.coord(i as i64).unwrap()) .collect_vec(); for pair in coords.iter().permutations(2).collect_vec() { let (a, b) = (pair[0], pair[1]); let offset = (a.0 - b.0, a.1 - b.1); let mut i = 0; loop { let node_pos = (a.0 + i * offset.0, a.1 + i * offset.1); if !map.antinodes.set(node_pos.0, node_pos.1, b'#') { break; } i += 1; } } } map.antinodes.count(b'#') as u64 } #[cfg(test)] mod tests { use crate::*; use std::io::Cursor; const EXAMPLE: &str = &"............ ........0... .....0...... .......0.... ....0....... ......A..... ............ ............ ........A... .........A.. ............ ............"; #[test] fn problem1_example() { let c = Cursor::new(EXAMPLE); assert_eq!(problem1(c.lines()), 14); } #[test] fn problem2_example() { let c = Cursor::new(EXAMPLE); assert_eq!(problem2(c.lines()), 34); } }